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\title{Incidence bounds in positive characteristic via valuations and distality} \alttitle{Bornes d'incidence en caractéristique positive par les valuations et la distalité}


\subjclass{03C98, 03C45, 05D99}
\keywords{Szemerédi-Trotter, incidence bounds, distality, Elekes-Szabó}


\author[\initial{M.} \lastname{Bays}]{\firstname{Martin} \lastname{Bays}}
\address{Mathematisches Institut\\
und Institut f\"ur Mathematische Logik \\
und Grundlagenforschung,\\
Fachbereich Mathematik\\
und Informatik, Universit\"at M\"unster,\\
Einsteinstrasse 62,\\
48149 Muenster, Germany}
\email{mbays@sdf.org}
\thanks{Bays was supported in part by the Deutsche Forschungsgemeinschaft (DFG, German Research Foundation) under Germany's Excellence Strategy EXC 2044-390685587, Mathematics M\"unster: Dynamics-Geometry-Structure}

\author[\initial{J-F.} \lastname{Martin}]{\firstname{Jean-François}
\lastname{Martin}}
\address{Université Paris-Saclay,\\
Paris, France}


\begin{abstract}
We prove distality of quantifier-free relations on valued fields with finite residue field. By a result of Chernikov--Galvin--Starchenko, this yields Szemerédi--Trotter-like incidence bounds for function fields over finite fields. We deduce a version of the Elekes--Szabó theorem for such fields.
\end{abstract}
\begin{altabstract}
Nous démontrons la distalité des relations sans quantificateur sur les corps valués de corps résiduel fini. D'après un résultat de Chernikov--Galvin--Starchenko, cela implique des bornes d'incidence de type Szemerédi--Trotter pour les corps de fonctions sur les corps finis. Nous en déduisons une version du théorème d'Elekes--Szabó pour de tels corps.
\end{altabstract}

\datereceived{2021-07-05}
\dateaccepted{2022-10-31}

\editor{X. Caruso}

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\dateposted{2023-10-02}
\begin{document}

\maketitle

\section{Introduction}

We obtain the following incidence bound.

\begin{theo}\label{t:SzTBasic}
Let $p$ be a prime, and let $K$ be a finitely generated extension of $\F_p$. Let $E \subseteq K^n \times K^m$ be the zero set of a set of polynomials in $K[x_1,\,\ldots,\,x_{n+m}]$. Let $d,s \in \N$ and suppose $E$ is $K_{d,s}$-free, i.e.\ if $A\times B \subseteq E$ then $|A| < d$ or $|B| < s$.

Then there exists $\epsilon > 0$ (which can in principle be calculated for a given $K$ as a function of the number and degrees of the polynomials defining $E$) and $C > 0$ such that for any finite subsets $A \subseteq K^n$ and $B
\subseteq K^m$,
\[
|E \cap (A \times B)| \leq C\left(|A|^{1-\epsilon}
|B|^{\frac{d-1}d(1+\epsilon)} + |A| + |B|\right).
\]
\end{theo}

\subsection{Background and motivation}
The Szemerédi--Trotter theorem bounds the number of point-line incidences between a set $P$ of points and a set $L$ of lines in the real plane. We state a version with an explicit bound, \cite[Theorem~8.3]{TaoVu}:

\begin{enonce}{Fact} \label{f:STOrig}
For any finite $P$ and $L$,
\[
\left|\left\{ (p,l) \in P \times L : p \in l\right\}\right|
\leq 4|P|^{\frac23}|L|^{\frac23}+4|P|+|L|.
\]
\end{enonce}

Statements of the form of Theorem~\ref{t:SzTBasic} can be seen as generalisations of this, replacing the point-line incidence relation with other algebraic binary algebraic relations. For characteristic 0 fields, such results were proven first in~\cite[Theorem~9]{ES}, and subsequently strengthened in~\cite[Theorem~1.2]{FoxEtAl}. Using such bounds for binary relations, Elekes--Szabó~\cite{ES} obtained analogous bounds for ternary algebraic relations.

In positive characteristic, versions of Fact~\ref{f:STOrig} have been proven (\cite{BKT,SZ}) where one restricts to sets which are small compared to the characteristic. This is related to the sum-product phenomenon in fields, where finite fields are known to be the only obstruction (\cite{BKT}, \cite[Theorem~2.55]{TaoVu}).

Meanwhile, a special case of results in~\cite{CGS} and~\cite[Section~2]{CS-ES1d} yields a version of Theorem~\ref{t:SzTBasic} in characteristic 0 by seeing it as a consequence of the fact that the complex field is a reduct of a \emph{distal} structure, namely the real field. Distality is a notion originating in model theory which imposes a certain combinatorial restriction on the complexity of definable sets in a structure; this notion and its incidence theoretic implications are summarised in Section~\ref{s:CSbackground} below. It would be surprising if the positive characteristic results mentioned in the previous paragraph, which require an unbounded characteristic, could be seen as instances of distality. We consider instead the orthogonal situation of a function field over a finite field, and we prove Theorem~\ref{t:SzTBasic} by finding sufficient distality to trigger the incidence bounds of~\cite{CGS}. We obtain this distality using elementary notions from the model theory of valued fields, and in fact our results apply more generally to any valued field with finite residue field. It follows from~\cite{KSW} that a positive characteristic valued field with finite residue field is not NIP, and so is not the reduct of a distal structure; this forces us to use a more local notion of distality.

Our motivation for considering these fields is~\cite[Section~5]{Hr-psfDims}, which suggests a unifying explanation for all the results on existence of bounds described above: they are all incarnations of {\em modularity} in the model-theoretic sense, and they are consistent with a Zilber dichotomy statement of the form ``any failure of modularity arises from an infinite pseudofinite field''. In other words, unboundedly large finite fields should be the cause of any failure of the bounds. As a special case, this would suggest that for a field $K$ of characteristic $p > 0$ which has finite
\dfn{algebraic part} $\K \cap \F_p^\alg$, incidence bounds and Elekes--Szabó results should go through as in characteristic 0.

We partially confirm this only in the special\footnote{See Proposition~\ref{p:latentFields}.} case of fields admitting finite residue field. However, in Theorem~\ref{t:ES} we do confirm for such $K$ that an Elekes--Szabó result applies: a mild strengthening of Theorem~\ref{t:SzTBasic} suffices as input to the proof of one of the main results of~\cite{BB-cohMod}, yielding Elekes--Szabó bounds for algebraic relations of arbitrary arity and codimension in $K^n$ which do not arise from 1-dimensional algebraic groups.

\subsection*{Acknowledgements}
Thanks to Artem Chernikov and Sergei Starchenko for conversation which launched the project, to Sylvy Anscombe, Philipp Dittmann, Udi Hrushovski, and Silvain Rideau--Kikuchi for miscellaneous helpful conversation, and to Elisabeth Bouscaren for matchmaking and sanity checking. Thanks also to Martin Hils for pointing out an error in the bounds in Remark~\ref{r:bounds} in an earlier version of the paper.



\section{Preliminaries}

We use basic notions and notation from model theory, as presented in e.g.~\cite[Chapter~1]{TZ}.

Let $\Lang$ be a (possibly many-sorted) first order language and $T$ a complete $\Lang$-theory.

\begin{notation}
If $\M \vDash T$ and $B \subseteq \M$ and $x=(x_1,\,\ldots,\,x_n)$ is a tuple of variables of sorts $S_1,\,\ldots,\,S_n$, we write $B^x$ for $\prod_i (S_i(\M) \cap B)$. We write $|x|$ for the length $|x| = n$ of the tuple.

For a set $B$, we write $B_0 \subseteq_{\fin} B$ to mean that $B_0$ is a finite subset of $B$.

For a formula $\phi$, we define $\phi^0 := \neg\phi$ and $\phi^1 := \phi$.

If $\phi(x;y)$ is a partitioned formula and $b \in \M^x$ and $A \subseteq \M$, we set $\tp_\phi(b/A) := \{ \phi(x,c)^\eps : c \in A^y;\; \eps \in \{0,1\};\; \M
\vDash \phi(b,c)^\eps \}$. The partitioning will often be left implicit.
\end{notation}

\vspace*{20pt} 
\pagebreak

\section{Distality}
\subsection{Distal cell decompositions}\label{s:CSbackground}
We recall the following definition from~\cite{CGS}:

\begin{defi}
Let $A$ and $B$ be sets. A binary relation $E \subseteq A \times B$ {\em admits a distal cell decomposition} with exponent $t \in \R$ if there exist $s \in \N$ and finitely many relations $\Delta_i \subseteq A \times B^s$ and $C \in \R$ such that for every $B_0 \subseteq_{\fin} B$, $A$ can be written as a (not necessarily disjoint) union of $\leq C|B_0|^t$ subsets of the form $\Delta_i(c)$ for $c \in {B_0}^s$, each of which is {\em cut} by no $E(b)$ for $b \in B_0$, i.e.\ $\Delta_i(c) \subseteq E(b)$ or $\Delta_i(c) \cap E(b) = \emptyset $.
\end{defi}

It was proven in~\cite{CGS} that relations admitting distal cell decompositions enjoy certain incidence bounds. For our purposes, the following version of this deduced in~\cite[Theorem~2.6,2.7(2)]{CS-ES1d} is most relevant.

A binary relation $E \subseteq A \times B$ is \dfn{$K_{d,s}$-free} if it contains no subset $A_0 \times B_0$ with $|A_0| = d$ and $|B_0| = s$.

\begin{enonce}{Fact} \label{f:distInc}
Let $E \subseteq A \times B$ be $K_{d,s}$-free and admit a distal cell decomposition with exponent $t$. Then for $A_0 \subseteq_{\fin} A$ and $B_0 \subseteq_{\fin} B$,
\[
|E \cap (A_0 \times B_0)| \leq O_E\left(|A_0|^{\frac{(t-1)d}{td-1}}
|B_0|^{\frac{td-t}{td-1}} + |A_0| + |B_0|\right).
\]
\end{enonce}

\subsection{Distal subsets}

\begin{defi}
Let $\M \vDash T$. Let $\phi(x;y)$ be an $\Lang(\M)$ formula, and let $A,B \subseteq \M$ be subsets.
\begin{itemize}
\item An $\Lang$-formula $\zeta_\phi(x;z)$ is a \dfn{uniform strong honest
definition} (\dfn{USHD}) for $\phi$ on $A$ over $B$ if for any $a \in A$ and finite subset $B_0 \subseteq_{\fin} B$ with $|B_0| \geq 2$, there is $d \in {B_0}^z$ such that $\tp(a/B_0) \ni \zeta_\phi(x,d) \vdash \tp_\phi(a/B_0)$.

\item We omit ``on $A$'' in the case $A = \M$.

\item We omit ``over $B$'' in the case $B=A$.

\item $A$ is \dfn{distal in} $\M$ if every $\Lang(A)$-formula $\phi(x;y)$ has a USHD on $A$.
\end{itemize}
\end{defi}

The notion of a strong honest definition comes from~\cite{CS-extDefII}. We work with USHDs rather than directly with distal cell decompositions in order to be able to reduce to one variable (Lemma~\ref{l:distal1}), and because dealing with a single formula is more convenient for many purposes. As the following remark makes explicit, there is little difference between the two notions.

\begin{rema}\label{r:distDist}
An $\Lang$-formula $\phi(x;y)$ has a USHD on $A$ over $B$ if and only if the binary relation $E := \phi(A;B) \subseteq A^x\times B^y$ admits a distal cell decomposition where the $\Delta_i$ are themselves defined by $\Lang$-formulas. The restriction $|B_0| \geq 2$ allows multiple $\Delta_i$ to be coded as one formula, a trick we will use repeatedly; explicitly, if $\delta_i(x,z_i)$ define $\Delta_i$, then
\[
\zeta\left(x,z_1,\,\ldots,\,z_s,w_1,\,\ldots,\,w_s,w'_1,\,\ldots,\,w'_s\right) :=
\bigwedge_i \left(\delta_i(x,z_i) \leftrightarrow w_i = w'_i\right)
\]
is a USHD for $\phi$ on $A$ over $B$.

In particular, if $A \subseteq \M$ is distal in $\M$, then the trace on $A$ of any $\Lang(A)$-formula $\phi(x,y)$ admits a distal cell decomposition.
\end{rema}

\subsection{Reductions}

\begin{lemm}\label{l:distal1}
A subset $A \subseteq \M$ is distal in $\M$ if and only if any $\Lang$-formula $\phi(x;y)$ with $|x| = 1$ has a USHD on $A$.
\end{lemm}

\begin{proof}
First, it follows by an inductive argument from the 1-variable case that any $\Lang$-formula has a USHD on $A$; we refer to the proof of~\cite[Proposition~1.9]{ACGZ} for this argument.

It remains to deduce that any $\Lang(A)$-formula has a USHD on $A$, but it follows directly from the definition that if $\phi(x;y,z)$ has a USHD on $A$ and $a \in A^z$, then $\phi(x;y,a)$ has a USHD on $A$.
\end{proof}


\begin{lemm}\label{l:dd-feq}
Let $\M$ be an $\Lang$-structure. Let $S$ and $\widetilde {S}$ be $\Lang$-sorts and let $f : \widetilde {S} \rightarrow S$ be an $\Lang$-definable function with uniformly finite fibres, say $|f^{-1}(b)| \leq N$ for all $b \in f(\widetilde {S}(\M))$. Suppose $B \subseteq f(\widetilde {S}(\M))$, and let $\widetilde {B} := f^{-1}(B) \subseteq \widetilde {S}(\M)$.

Let $A \subseteq \M^x$ and let $\phi(x,y)$ be an $\Lang$-formula such that $\phi(x;f(z))$ has a USHD on $A$ over $\widetilde {B}$. Then $\phi(x;y)$ has a USHD on $A$ over $B$.
\end{lemm}

\begin{proof}
Say $\zeta(x,w)$ is a USHD for $\phi(x;f(z))$ over $\widetilde {B}$.

Let $B_0 \subseteq_{\fin} B$ and $a \in A$. Then $\widetilde {B}_0 := f^{-1}(B_0)$ is a finite subset of $\widetilde {B}$, so there is $\widetilde {d}$ such that $\tp(a/\widetilde {B}_0) \ni \zeta(x,\widetilde {d}) \vdash
\tp_{\phi(x;f(z))}(a/\widetilde {B}_0) \vdash \tp_{\phi(x;y)}(a/B_0)$.

Let $d := f(\widetilde {d})$. Then $|f^{-1}(d)| \leq N^{|w|}$, and so there is $l < N^{|w|}$ and $\epsbar_0 \in \{0,1\}^l$ and $\b_0 \in (B_0)^l$ such that $\theta_{l,\epsbar_0}(w,d,\b_0)$ has the minimal number of realisations amongst the formulas
\[
\theta_{n,\epsbar}(w,d,\b) := \left(f(w) = d \wedge \forall x. \left(\zeta(x,w) \rightarrow
\bigwedge_{i=1}^n \phi(x,b_i)^{\eps_i}\right)\right)
\]
which hold of $\widetilde {d}$, with $n \in \N$ and $\epsbar \in \{0,1\}^n$ and $\b \in (B_0)^n$. The bound $l < N^{|w|}$ follows from the observation that if such a formula does not have the minimal number of realisations, then a single new instance of $\phi$ can be added to reduce the number of realisations. By the minimality, we have for any $b \in B_0$ that $\theta_{l,\epsbar_0}(w,d,\b_0) \vdash \forall x. (\zeta(x,w) \rightarrow
\phi(x,b)^\eps)$ for some $\eps \in \{0,1\}$.

So $\tp(a/B_0) \ni \exists w. (\theta_{l,\epsbar_0}(w,d,\b_0) \wedge \zeta(x,w))
\vdash \tp_{\phi(x;y)}(a/B_0)$. Coding the finitely many such formulas with $l < N^{|w|}$ and $\epsbar_0 \in \{0,1\}^l$ into a single formula, we therefore obtain a USHD for $\phi(x;y)$ on $A$ over $B$.
\end{proof}

\begin{rema}
The finiteness assumption in Lemma~\ref{l:dd-feq} is necessary. Consider for example the structure $(X,O_X;<)$ where $X$ is a set, $O_X$ is the set of linear orders on $X$, and $x<_ox'$ is the corresponding ternary relation. Let $\pi_1 : X \times O_X \rightarrow X$ be the projection. As one may see by considering automorphisms, the induced structure on $X$ is trivial, so $x = y$ has no USHD on $X$ over $X$. But $x = \pi_1(z)$ has a USHD on $X$ over $X\times O_X$ (since if $X_0 \subseteq_{\fin} X$ and $o \in O_X$, then $\tp_=(x/X_0)$ is implied by the $<_o$-cut of $x$ in $X_0$).
\end{rema}


\subsection{Remarks}
We add some further remarks concerning these definitions, which will not be used subsequently.

\begin{rema}\label{r:distalElem}
Suppose $A$ is distal in an $\Lang$-structure $\M$. Then this is expressed in the $\Lang_P$-theory of $(\M;A)$, where $P$ is a new predicate interpreted as $A$; i.e.\ if $(\M';A') \equiv (\M;A)$, then $A'$ is distal in $\M'$.
\end{rema}

\begin{rema}
By~\cite[Theorem~21]{CS-extDefII}, $\Th(\M)$ is distal if and only if $\M$ is distal in $\M$. (No saturation assumption is needed here, thanks to Remark~\ref{r:distalElem}.)
\end{rema}

\begin{rema}
Distality in $\M$ of a subset $A \subseteq \M$ is equivalent to distality of the induced structure $(A;(\phi(A)_{\phi \text{ an $\L$-formula}}))$ if this structure admits quantifier elimination, but in general is much weaker. We could say that distality of a subset means that it has ``quantifier-free distal induced structure''.
\end{rema}

\begin{exam}\label{e:indSeq}
If $A = (a_i)_{i\,\in\,I} \subseteq \M$ is an $\emptyset $-indiscernible sequence which is not totally indiscernible, and this is witnessed by an $\Lang$-formula $\theta_<$ with $\M \vDash \theta_<(a_i,a_j) \Leftrightarrow i<j$, then $A$ is distal in $\M$.
\end{exam}

\begin{rema}
The argument of~\cite{CS-extDefII} to obtain uniformity of honest definitions goes through in this setting. Namely, if $A$ is a subset of a model $\M$ of a complete NIP $\Lang$-theory $T$, and the $\Lang_P$-structure $(\M;A)$ is $|T|^+$-saturated, then $A$ is distal in $\M$ if and only if for any singleton $a \in A$ and any subset $B \subseteq A$, $\tp^{\M}(a/B)$ is compressible in the sense of~\cite{simon-decomposition}. This follows from a ``$(p,q)$-argument'' and transitivity of compressibility.


It follows in particular that Example~\ref{e:indSeq} can be generalised slightly when $\M$ is NIP: any $\emptyset $-indiscernible sequence which is not totally indiscernible is distal in $\M$.
\end{rema}


\begin{question}
The following question was asked by Hrushovski and Pillay. By a result of Simon, an NIP theory is distal if and only if every generically stable Keisler measure is smooth. Does a version of this result go through for distality of subsets of NIP structures? Is $A$ distal in $\M$ if and only if every generically stable Keisler measure on $\Th_{\Lang_P}(\M,A)$ with $\mu(\neg P)=0$ is smooth? This might provide an alternative route to Theorem~\ref{t:fin-res-distal}.
\end{question}

\section{Fields admitting valuations with finite residue field} 
By classical results in valuation theory, a valuation on a field $K$ can be extended to any finite extension of $K$ with a finite extension of the residue field~\cite[Theorem~3.1.2, Corollary~3.2.3]{EnglerPrestel}, and can be extended to the transcendental extension $K(X)$ without extending the residue field~\cite[Corollary~2.2.3]{EnglerPrestel}. Since $\F_p$ and $\Q$ admit valuations with finite residue field (respectively trivial and $p$-adic), we inductively obtain:\

\begin{lemm}\label{l:fgRes}
Let $K$ be a finitely generated field. Then $K$ admits a valuation with finite residue field.
\end{lemm}

If $K$ is a valued field of characteristic $p>0$, then the induced valuation on the algebraic part $K\cap \F_p^\alg$ is trivial. So a positive characteristic field which admits a valuation with finite residue field has finite algebraic part. However, the converse fails.

\begin{prop}\label{p:latentFields}
For any prime $p$, there exists an algebraic extension $L \geq \F_p(t)$ such that $L\cap
\F_p^\alg = \F_p$ but no valuation on $L$ has finite residue field.
\end{prop}
\begin{proof}
We work in an algebraic closure $\F_p(t)^\alg$ of $\F_p(t)$. Let $\wp : \F_p(t)^{\alg} \rightarrow \F_p(t)^\alg$ be the Artin--Schreier map $\wp(x) := x^p-x$, an additive homomorphism with kernel $\F_p$.

\begin{enonce*}{Claim}
$\deg(\F_p(t,(\wp^{-1}(t^a))_{a > 0}) / \F_p(t))$ is infinite.
\end{enonce*}
\begin{proof}
By~\cite[Theorem~8.3]{Lang-algebra}, it suffices to see that $\{ t^a | a > 0\}$ is not contained in any finite union of additive cosets of $\wp(\F_p(t))$. Let $a,b \in \N \setminus p\N$ be distinct. Let $\beta_{a,b} := \sum_{i\,\geq\,0} (t^{ap^i} - t^{bp^i}) \in \F_p[[t]]$. Then $\wp(\beta_{a,b}) = t^b - t^a$. Now $\beta_{a,b} \notin \F_p(t)$, since there are arbitrarily long intervals between exponents with non-zero coefficient in this power series. So $(t^a)_{a\,\in\,\N \setminus p\N}$ lie in distinct cosets of $\wp(\F_p(t))$.
\end{proof}

We write $\res$ for the residue field map associated to a chosen valuation $v$ on a field $K$, and $\res(K)$ for the corresponding residue field.

\begin{enonce*}{Claim}
Let $K' \geq K \geq \F_p(t)$ be finite field extensions, and suppose $K' \cap
\F_p^\alg\linebreak = \F_p$. Let $v$ be a valuation on $K$ with $\res(K)$ finite.

Then there exists a finite field extension $K'' \geq K'$ such that $K'' \cap \F_p^\alg = \F_p$ but for any extension of $v$ to $K''$, $\res(K'') \gneq \res(K)$.
\end{enonce*}

\begin{proof}
The valuation $v$ is non-trivial, so say $v(s) > 0$. So $v$ induces the $s$-adic valuation on $\F_p(s) \leq K$. Now $s$ is transcendental, so $t$ is algebraic over $s$, so $K$ is also a finite extension of $\F_p(s)$. So we may assume without loss that $v$ restricts to the $t$-adic valuation on $\F_p(t)$.

Since $\res(K)$ is finite, it is not Artin--Schreier closed; say $\alpha \in \res(K) \setminus \wp(\res(K))$. Say $\res(\bar\alpha) = \alpha$.

Since $\deg(K'/\F_p(t))$ is finite, it follows from the above Claim that
\[
\deg\left(K'\left(\wp^{-1}(\bar\alpha),\left(\wp^{-1}\left(\bar\alpha + t^a\right)\right)_{a\,>\,0}\right)/K'\right)
\]
is infinite. So say $a>0$ is such that $K'' := K(\wp^{-1}(\bar\alpha+t^a)) \not\subseteq K'(\F_{p^p})$. Then by considering degrees, $K'' \cap \F_p^\alg = \F_p$. But for any extension of $v$ to $K''$,
\[
\wp\left(\res\left(\wp^{-1}\left(\bar\alpha+t^a\right)\right)\right) = \res\left(\bar\alpha+t^a\right) = \alpha \notin
\wp(\res(K)),
\]
so $\res(K'') \gneq \res(K)$.
\end{proof}

Now we recursively construct a chain $K_0 := \F_p(t) \leq K_1 \leq\,\ldots $ of finite extensions of $\F_p(t)$. Let $\eta : \omega \times \omega \rightarrow \omega$ be a bijection such that $\eta(i,j) \geq i$ for all $i,j$.

Note that $\F_p(t)$ admits only countably many valuations (identifying a valuation with its valuation ring); indeed, as above, each non-trivial valuation is a finite extension of the $s$-adic valuation on some $\F_p(s)\leq \F_p(t)$; there are only countably many choices for $s$, and only finitely many ways to extend a valuation to a finite extension (\cite[Theorem~3.2.9]{EnglerPrestel}). Hence also there are also only countably many valuations on each $K_i$. Once $K_i$ is constructed, let $\{v_{i,j} : j \in \omega\}$ be the set of valuations on $K_i$ with finite residue field.

Suppose $k=\eta(i,j)$ and $K_k$ has been constructed. Let $K_{k+1} \geq K_k$ be an extension as in the second Claim for the extensions $K_k \geq K_i \geq
\F_p(t)$ and the valuation $v_{i,j}$ on $K_i$.

Now let $K_\omega := \bigcup_{k\,<\,\omega} K_k$. We have $K_\omega \cap \F_p^\alg = \F_p$ since this holds for each $K_k$.

Suppose $v$ is a valuation on $K_\omega$ with finite residue field. Then $\res(K_\omega) = \res(K_i)$ say, and the restriction of $v$ to $K_i$ is $v_{i,j}$ say. Then $\res(K_{\eta(i,j)+1}) = \res(K_i)$, contradicting the construction.
\end{proof}

\begin{rema}
One might expect that a Zorn argument could replace the recursive construction of the previous Proposition, i.e.\ that any maximal regular extension of $\F_p(t)$ has no valuation with finite residue field. But $\F_p((t^\Q)) \cap \F_p(t)^\alg$ is a counterexample. Thanks to Zoé Chatzidakis for pointing this out.
\end{rema}

\section{Distality in \texorpdfstring{$\ACVF$}{ACVF} of subfields with finite residue field}

\subsection{Uniform Swiss cheese decompositions}
Let $L$ be a non-trivially valued algebraically closed field. Write $v$ for the valuation map and $\res$ for the residue field map. We consider $L$ as an $\Ldiv := \{+,-,\cdot,|,0,1\}$-structure, where $x|y \Leftrightarrow v(x) \leq v(y)$; by a result of Robinson, $L$ has quantifier elimination in this language. An open resp.\ closed \dfn{ball} in $L$ is a definable set of the form $\{ x : v(x-a) > \alpha \}$ resp.\ $\{ x : v(x-a) \geq \alpha \}$, where $a \in L$ and $\alpha \in v(L) \cup \{-\infty,+\infty\}$.

\begin{enonce}{Fact}[{Canonical Swiss cheese decomposition~\cite[Theorem~3.26]{Holly}}] \label{f:swiss}
Any boolean combination of balls can be represented as a finite disjoint union of ``Swiss cheeses'' $\bigcupdot_{i\,<\,k} (b_i \setminus \bigcupdot_{j\,<\,k_i} b_{ij})$, where the $b_i$ are balls, each $b_{ij}$ is a proper sub-ball of $b_i$, for each $i$ the $b_{ij}$ are disjoint, and no $b_i$ is equal to any $b_{i'j}$. This representation is unique up to permutations.
\end{enonce}

We call the $b_i$ the ``rounds'' and the $b_{ij}$ the ``holes'' of a Swiss cheese decomposition, and we say such a decomposition has \dfn{complexity} $\leq N$ if there are $k\leq N$ rounds each with $k_i\leq N$ holes. Let $\phi(x,y)$ be an $\Ldiv$-formula with $|x| = 1$. For any $a \in L$, it follows directly from quantifier elimination that $\phi(L,a)$ is a boolean combination of balls. We will need the following form of uniformity in $a$ of the Swiss cheese decompositions.

\begin{lemm}\label{l:ACVFQE-uniformity}
There are $N$ and $d$ depending only on $\phi$ such that for all $a \in L^y$, $\phi(L,a)$ has a Swiss cheese decomposition of complexity $\leq N$, each round and each hole of which contains a point in a field extension of the subfield generated by $a$ of degree dividing $d$.
\end{lemm}

\begin{proof}
By quantifier elimination, $\phi(x,a)$ is equivalent to a boolean combination of formulas of the form $\phi_i(x,a) := v(f_i(x,a)) < v(g_i(x,a))$ for polynomials $f_i,g_i \in \Z[x,y]$.

Now if $f_i(x,a)$ is non-constant, then $v(f_i(x,a)) = \sum_{j=1}^k v(x-\alpha_j)$ where $\alpha_1,\,\ldots,\linebreak\alpha_k \in L$ are the zeroes of $f_i(x,a)$. Similarly for the $g_i$. So the following claim shows that $\phi(x,a)$ is equivalent to a boolean combination of balls centred at the roots of the non-constant $f_i(x,a)$ and $g_i(x,a)$.

\begin{enonce}{Claim}
Let $s \in \N$, $\gamma_1,\,\ldots,\,\gamma_s \in L$, $n_1,\,\ldots,\,n_s \in \Z$, and $\nu
\in v(L)$. Then the affine linear constraint $\psi(x) := \sum_{i=1}^s n_i v(x-\gamma_i) < \nu$ is equivalent to a boolean combination of balls centred at the $\gamma_i$.
\end{enonce}

\begin{proof}
We prove this by induction on $s$, the case $s=0$ being trivial.

There are only finitely many possible order types for $\eps := v(x-\gamma_1)$ over $\{ v(\gamma_1-\gamma_i) : i > 1 \}$. Fix one such order type, and let $X$ be the set of $x$ for which $\eps$ has this order type. Since $X$ is itself a boolean combination of balls centred at $\gamma_1$, it suffices to show that $\phi(x)$ is equivalent on $X$ to a boolean combination of balls centred at the~$\gamma_i$.

If $\eps = v(\gamma_1-\gamma_i)$ for some $i>1$, then $\psi(x)$ is equivalent on $X$ to $\sum_{i=2}^s n_i v(x-\gamma_i)\linebreak < \nu - n_1v(\gamma_1-\gamma_i)$, and we conclude by the inductive hypothesis.

Otherwise, by the ultrametric triangle inequality, $v(x-\gamma_i) = \eps$ if $\eps < v(\gamma_1-\gamma_i)$, and $v(x-\gamma_i) = v(\gamma_1-\gamma_i)$ otherwise, so $\psi(x)$ is equivalent on $X$ to $nv(x-\gamma_1) < \nu'$ or $nv(x-\gamma_1) > \nu'$ for some $n \in \Z$ and $\nu' \in v(L)$.
\end{proof}

So $\phi(L,a)$ is a boolean combination of balls each having a point in an
extension of the subfield generated by $a$ of degree dividing
\[
d := \lcm_i
\left(\lcm\left(\deg_x f_i, \deg_x g_i\right)\right).
\]
Refining this boolean combination to the Swiss cheese decomposition, it follows that its rounds and holes also have this property. Indeed, since no ball is the union of finitely many subballs, the rounds and holes must appear in any expression for $\phi(L,a)$ as a boolean combination of balls.

We may assume $L$ is $\aleph_0$-saturated, and so by compactness we obtain a uniform bound on the number of rounds and holes, as required.
\end{proof}

\subsection{Compressing cheeses}
Let $B$ be the imaginary sort of $L$ consisting of balls, both open and closed, including the empty ball and its complement. We write $x \in b$ for the corresponding $\emptyset $-definable (in $\Leq$) membership relation $(\in) \subseteq L
\times B$.

Given $N \in \N$, let $S_N$ be the imaginary sort of $L$ which codes Swiss cheese decompositions of complexity at most $N$. This means that we have an associated $\emptyset $-definable membership relation, which we also write as $(\in)
\subseteq L \times S_N$, such that $c_1 = c_2$ iff $\{ x : x \in c_1 \} = \{ x : x \in c_2 \}$, and
setting
\[
X_N := \left\{(b_i)_{i\,<\,N},(b_{ij})_{i,j\,<\,N} : b_i,b_{ij} \in B \text{ are
as in Fact~\ref{f:swiss}}\right\} \subseteq B^{N(N+1)}
\]
we obtain a $\emptyset $-definable surjection $f_{S_N} : X_N \twoheadrightarrow S_N$ defined by $f_{S_N}((b_i)_i,(b_{ij})_{ij}) := [{ \text{code of } \bigcup_i (b_i \setminus
\bigcup_j b_{ij}) }]$. By Fact~\ref{f:swiss}, any $c \in S_N$ has a unique-up-to-permutation representation as a Swiss cheese decomposition of complexity $\leq N$, so $f_{S_N}$ has finite fibres.

With a view to proving Theorem~\ref{t:fin-res-distal}, for $K$ a valued subfield of $L$ with finite residue field and $d \in \N$, define $B_{K,d} \subseteq B$ to be the set of balls which contain an element of some finite field extension of $K$ within $L$ of degree dividing $d$ over $K$. Let $X_N(B_{K,d}) := X_N \cap {B_{K,d}}^{N(N+1)}$ and $S_N(B_{K,d}) := f_{S_N}(X_N(B_{K,d}))$.

\pagebreak
\begin{lemm}\label{l:B-rel-distal-local}
Let $N,d \in \N$.
\begin{enumerate}\romanenumi
\item\label{lemm5.4.1} $x \in y$ has a USHD over $B_{K,d}$.
\item\label{lemm5.4.2} $x \in f_{S_N}(y)$ has a USHD over $B_{K,d}$.
\item\label{lemm5.4.3} $x \in z$ has a USHD over $S_N(B_{K,d})$.
\end{enumerate}
\end{lemm}
\begin{proof}
\begin{itemize}\romanenumi
\item[\eqref{lemm5.4.1}]
By assumption, the residue field of $K$ is a finite field, say $\F_q$.

Let $B_0 \subseteq_{\fin} B_{K,d}$. Let $B_0' := \{ b \vee b' : b,b' \in B_0 \}$ where the join $b \vee b'$ is the smallest ball containing both $b$ and $b'$. By the ultrametric triangle inequality, $B_0'$ is then closed under join. Note that $B_0' \subseteq B_{K,d}$, since $B_{K,d}$ is upwards-closed.

Let $p \in L$. Let $b \in B_0' \cup \{L\}$ be minimal such that $p \in b$, and let $b_1,\,\ldots,\,b_s \in B_0'$ be the maximal proper subballs (if any) of $b$ in $B_0'$. Then
\[
\left(x \in b \wedge \bigwedge_{i=1}^s x \notin b_i\right) \vdash \tp_{x\,\in\,y}(p/B_0),
\]
and each $b_i$ is the join of two balls in $B_0$, and either the same goes for $b$ or $b=L$. So coding the finitely many possibilities yields a USHD as required if we can bound $s$ independently of $p$.

Assume $s > 1$. Say $p_i \in b_i$ is of degree dividing $d$ over $K$, and let $\alpha \in v(L)$ be the valuative radius of $b$. Then $v(p_i-p_j)=\alpha$ for $i\neq j$, since $b_i \vee b_j = b$ (in particular, $b \neq L$).

Then $i \mapsto \lambda_i := \res(\frac{p_i-p_1}{p_2-p_1})$ is an injection of $\{1,\,\ldots,\,s\}$ into $\res(L)$. Indeed, if $\lambda_i=\lambda_j$ then $\res(\frac{p_i-p_j}{p_2-p_1}) = 0$, so $v(p_i-p_j) > v(p_2-p_1) = \alpha$, so $i=j$.

Since each $\lambda_i$ is in the residue field of an extension of $K$ of degree dividing $d^3$, by the valuation inequality (\cite[Corollary~3.2.3]{EnglerPrestel}). each $\lambda_i$ is in an extension of $\res(K) = \F_q$ of degree $\leq d^3$, so $\lambda_i \in \F_{q^{d^3!}}$ for all $i$. So $s \leq q^{d^3!}$.

\item[\eqref{lemm5.4.2}] $x \in f_{S_N}(y)$ is equivalent, by the definition of $f_{S_N}$, to a certain boolean combination of the formulas $(x \in y_i)_{i\,<\,N(N+1)}$. So by~\eqref{lemm5.4.1}, coding these formulas yields a formula which is a USHD for $x \in f_{S_N}(y)$ over $B_{K,d}$.

\item[\eqref{lemm5.4.3}] Considering now $X_N$ as a sort and $y$ as a variable of sort $X_N$, it follows from~\eqref{lemm5.4.2} that $x \in f_{S_N}(y)$ has a USHD over $X_N(B_{K,d})$. Then we conclude by Lemma~\ref{l:dd-feq}.\qedhere
\end{itemize}
\end{proof}

\subsection{Concluding distality}

\begin{lemm}\label{l:fin-res-comp}
Let $L$ be a non-trivially valued algebraically closed field. Let $K \leq L$ be a subfield and suppose $\res(K)$ is finite. Let $\phi(x;y)$ be an $\Ldiv$-formula with $|x| = 1$. Then $\phi$ has a USHD over $K$.

Moreover, for any $r \geq 1$, $\phi$ has a USHD over the set $K_r \subseteq K^{\alg}
\subseteq L$ of points with degree over $K$ dividing $r$,
\[
K_r := \{ a \in L : \deg(K(a)/K) | r \}
\]
\end{lemm}

\begin{proof}
Let $N$ and $d$ be as in Lemma~\ref{l:ACVFQE-uniformity} for $\phi$. Then there is a $\emptyset $-definable function $h : L^y \rightarrow S_N$ such that $L^{\eqq} \vDash \forall x,y. (\phi(x,y) \leftrightarrow x \in h(y))$, and $h(K_r) \subseteq S_N(B_{K,dr})$.

By Lemma~\ref{l:B-rel-distal-local}$\MK$\eqref{lemm5.4.3}, say $\zeta(x,z'_1,\,\ldots,\,z'_s)$ is a USHD for $x \in y$ over $S_N(B_{K,dr})$. Then (an $\Ldiv$-formula equivalent to) $\zeta(x,h(z_1),\,\ldots,\,h(z_s))$ is a USHD for $\phi(x;y)$ over~$K_r$.
\end{proof}

\begin{theo}\label{t:fin-res-distal}
Let $K$ be a valued field with finite residue field.

Let $L \geq K$ be an algebraically closed valued field extension.

Then $K$ is distal in $L$, as is each $K_r$ defined as in Lemma~\ref{l:fin-res-comp}.
\end{theo}

\begin{proof}
We may assume that $L$ is non-trivially valued, as otherwise $K$ is finite and the result is trivial.

The result then follows from Lemma~\ref{l:fin-res-comp} and Lemma~\ref{l:distal1}.
\end{proof}

\begin{rema}
This does not reprove distality of $\Q_p$, because $\Q_p$ does not eliminate quantifiers in $\Ldiv$.
\end{rema}


\section{Incidence theory consequences}

\begin{theo}\label{t:SzT}
Let $K$ be a valued field with finite residue field. Let $E \subseteq K^n \times K^m$ be quantifier-free definable in $\Ldiv(K)$. Suppose $E$ omits $K_{d,s}$, where $d,s \in \N$. Then there exist $t$ (see Remark~\ref{r:bounds}) and $C>0$ such that for $A_0 \subseteq_{\fin} K^n$ and $B_0 \subseteq_{\fin} K^m$,
\[
|E \cap (A_0 \times B_0)| \leq C\left(|A_0|^{\frac{(t-1)d}{td-1}}
|B_0|^{\frac{td-t}{td-1}} + |A_0| + |B_0|\right).
\]

The same holds if $K$ is replaced by $K_r \subseteq K^{\alg}$ defined as in Lemma~\ref{l:fin-res-comp}.
\end{theo}


\begin{proof}
By Theorem~\ref{t:fin-res-distal} and Remark~\ref{r:distDist}, $E$ admits a distal cell decomposition, and we conclude by Fact~\ref{f:distInc}.
\end{proof}

The version of this stated in the introduction, Theorem~\ref{t:SzTBasic}, follows by considering Lemma~\ref{l:fgRes} and the special case that $E$ is defined as the zero set of polynomials over $K$, and setting $\epsilon := \frac1{dt-1}$.

\begin{rema}\label{r:bounds}
By examining the proof, in the case $n=1$ one can obtain a bound on the exponent of the resulting distal cell decomposition giving $t \leq 2(q^{d^3!}+1)$ where $q = |\res(K)|^r$ and $d$ is as in the proof of Lemma~\ref{l:fin-res-comp}. Indeed, this is the exponent arising from bounding the number of balls used in Lemma~\ref{l:B-rel-distal-local}$\MK$\eqref{lemm5.4.1}, and neither Lemma~\ref{l:B-rel-distal-local}$\MK$\eqref{lemm5.4.2} nor Lemma~\ref{l:dd-feq} increase the exponent (for the latter case, this follows from the structure of the proof, since each instance $\zeta(x,\widetilde {d})$ gives rise to a single instance of the eventual formula).

So we obtain the corresponding explicit bounds in Fact~\ref{f:distInc}. However, we have no reason to expect these bounds to be anything like optimal.

For $n>1$, calculating explicit bounds is complicated by the fact that when reducing to one variable a USHD for a quantified formula is used, so one needs a bound on the degrees in the quantifier-free formula obtained by quantifier elimination in ACVF. This quantifier elimination is primitive recursive~\cite{Weispfenning}, so in principle this could be done, yielding an effective algorithm for computing an exponent $t$ for a given $E$ (uniform in definable families). But we do not attempt to make this explicit here.

Instead, we illustrate the idea by showing that in the special case of Szemerédi--Trotter, $E = \{ ((x,y),(a,b)) : y=ax+b \}$, we can take $t := 4(q+1)$.

The proof of Lemma~\ref{l:B-rel-distal-local}$\MK$\eqref{lemm5.4.1} in this case gives a USHD $\zeta(y,x,\z)$ for $\phi(y;x,(a,b)) := (x,y)E(a,b)$ over $K$, expressing that $y$ is an element of a boolean combination of the points $z_{i,1}x+z_{i,2}$ and the balls spanned by pairs of such points, with at most $2(q+1)$ such points involved. Using coding to choose the form of the boolean combination, this has exponent $\leq 2(q+1)$.

By~\cite[Theorem~2.1]{Weispfenning}, if an $\Ldiv$ qf-formula $\psi(x,\y,\z)$ is linear in $x,\y$, i.e.\ each polynomial has degree~1 in $x$ and each $y_i$, then $\exists x. \psi(x,\y,\z)$ is equivalent modulo $\ACVF$ to a qf-formula linear in $\y$.

Now the formula $\zeta(y,x,\z) \rightarrow (x,y)Ew$ is linear in $x,y$, so $\forall y. (\zeta(y,x,\z) \rightarrow (x,y)Ew)$ is equivalent to a qf-formula which is linear in $x$. Similarly $\forall y. (\zeta(y,x,\z) \rightarrow \neg(x,y)Ew)$ is equivalent to a qf-formula linear in $x$, and the two can be coded into a single qf-formula linear in $x$. This then itself admits (by the $n=1$ case of the present Remark with $d=1$) a USHD $\xi(x,\w)$ over $K$ of exponent $\leq 2(q+1)$. Then $\xi(x,\w) \wedge \zeta(y,x,\z)$ is a USHD for $E$ over $K$ of exponent $\leq 2(q+1) + 2(q+1) = 4(q+1)$. In symmetric form, this gives a bound of $O(N^{\frac32 -
\frac1{16(q+1)-2}})$ on the number of incidences of $N$ lines and $N$ points.

As a final remark, note that although Theorem~\ref{t:SzT} does apply in characteristic 0, e.g.\ to $K=\Q_p$, the bounds we obtain in this way are worse than those obtained from~\cite{FoxEtAl} by embedding $\Q_p$ in $\C=\R^2$, even for $p=2$.
\end{rema}

\begin{question}
Is the dependence on $q$ in these bounds necessary? For example, does there exist $\epsilon>0$ such that for all primes $p$ there exists $C$ such that for all $X,A \subseteq \F_p(t)^2$ we have $|\{((x,y),(a,b)) \in X\times A : y=ax+b\}| \leq C\max(|X|,|A|)^{\frac32-\epsilon}$? (Remark~\ref{r:bounds} yields a bound depending on $p$ of $\epsilon =
\frac1{16p+14}$ in this case. Meanwhile one can obtain a lower bound exponent of $\frac43$ by considering a rectangular example with bounded degree polynomials, $\F_p[t]_{<\,n} \times \F_p[t]_{<\,2n}$.)
\end{question}

\section{Elekes--Szabó consequences}

Let $K_0$ be a field admitting a valuation with finite residue field (e.g.\ a function field over a finite field). Let $\U$ be a non-principal ultrafilter on $\omega$. Define
\[
K' := \left((K_0)^\U\right)^\alg \leq \left((K_0)^\alg\right)^\U =: K.
\]
For $r\geq 1$, let
\[
K_r := \left\{ a \in (K_0)^\alg : \deg(K_0(a)/K_0) \middle| r \right\}.
\]
So (by \Los's theorem) we have $K' = \bigcup_{r\,\in\,\omega} (K_r)^\U$.

We work with the setup of~\cite[2.1]{BB-cohMod}, with $(K_0)^\alg$ in place of $\C$, and in a countable language in which each of these internal sets $(K_r)^\U \subseteq K$ is definable.

\begin{theo}\label{t:ES}
Let $K_0$ be a field admitting a valuation with finite residue field. Let $V \subseteq \A^n$ be an affine algebraic variety defined over $K_0$ of dimension $d$. Then at least one of the following holds:
\begin{enumerate}\romanenumi
\item $V$ admits a powersaving on $K_0$: there exist $C,\eps > 0$ such that
for all $X_i \subseteq_{\fin} K_0$, $i=1,\,\ldots,\,n$, we have
\[
\left|V(K_0) \cap \prod_i X_i\right| \leq C\left(\max_i |X_i|\right)^{d-\eps}.
\]
\item $V$ is \emph{special}: $V$ is in co-ordinatewise correspondence\footnote{As defined in~\cite[Definition~1.1]{BB-cohMod}} with a product $\prod_i H_i \linebreak\leq \prod {G_i}^{n_i}$ of connected subgroups of $H_i$ of powers $G_i$ of 1-dimensional algebraic groups.
\end{enumerate}
\end{theo}


\begin{proof}
Let $K' \leq K$ be as above. Also let $C_0 \leq K'$ be a countable algebraically closed subfield over which $V$ is defined.

The proof in~\cite{BB-cohMod} goes through, but using Theorem~\ref{t:SzT} in place of~\cite[Theorem~2.14]{BB-cohMod}, and with~\cite[Theorem~3.3.1]{EvansHrushovski} replacing~\cite[Proposition~A.4]{BB-cohMod}. We describe the necessary changes.

Firstly, \cite[Theorem~2.15]{BB-cohMod} goes through in the case that $X_i
\subseteq ((K_r)^\U)^{n_i}$ for some $r$ ($i=1,2$). The proof is identical, using Theorem~\ref{t:SzT}; the sublinearity of the dependence on $s$ where $K_{2,s}$ is omitted, discussed after~\cite[Theorem~2.14]{BB-cohMod}, also holds here: this is described in~\cite[Remark~2.7$\MK$(2),Corollary~2.8]{CS-ES1d}, and is proven explicitly in~\cite[Theorem~2.6]{CPS-ES}. (In fact this sublinearity isn't necessary for the present 1-dimensional case.)

Now~\cite[Theorem~5.9]{BB-cohMod} goes through for $P \subseteq (K')^{<\omega}$. The proof is identical, except that in the proof of~\cite[Proposition~5.14]{BB-cohMod}, since $\a,\d \in (K')^{<\omega}$, already $\a,\d \in ((K_r)^\U)^{<\omega}$ for some $r$, and this passes through to the types $X_i$ since $(K_r)^\U$ is definable, so the above restricted form of~\cite[Theorem~2.15]{BB-cohMod} applies.

Next, $\End^0_{C_0}(G)$ must be redefined as the skew-field of quotients of $\End_{C_0}(G)$ (this agrees with $\Q\otimes\End_{C_0}(G)$ in characteristic 0); see~\cite[3.1]{EvansHrushovski} for discussion of the possibilities.

Finally, we indicate how to circumvent the use of~\cite[Proposition~A.4]{BB-cohMod}, which is proven only in characteristic 0, in the 1-dimensional case. Where this is applied in~\cite[Proposition~6.1]{BB-cohMod}, we have $a_i \in K'$ ($i=1,\,\ldots,\,n$) such that $\G_\a = \{ \acl^0(a_i)\linebreak : i \}$ embeds in a projective subgeometry of the $\acl^0$-geometry $\G_K$ of $K$. (Here we have $a_i \in K'$ rather than $a_i \in K^{<\,\omega}$, as this is what arises in the proof, via~\cite[Theorem~7.4]{BB-cohMod}, in the 1-dimensional case corresponding to the statement of the current theorem.) By~\cite[Theorem~3.3.1]{EvansHrushovski}, there is a 1-dimensional algebraic group $G$ over $C_0$ and generic $\x \in G^m$ over $C_0$ (where $m=\dim(\G_\a)$) and $A \in \operatorname{Mat}_{n,m}(\End(G))$ such that, setting $\h := A\x$, we have $\acl^0(h_i) = \acl^0(a_i)$. Then $\operatorname{loc}^0(\h) = AG^m$ is a connected algebraic subgroup of $G^n$, as required.

The rest of the proof goes through unchanged.
\end{proof}

\begin{rema}
The only obstruction to pushing this to higher dimension, i.e. to a version of~\cite[Theorem~1.11]{BB-cohMod}, is the need to generalise the higher dimensional version of Evans--Hrushovski~\cite[Proposition~A.4]{BB-cohMod} to positive characteristic.

Meanwhile, the proof of the converse direction (showing that every special variety admits no powersaving) makes essential use of the characteristic 0 assumption in~\cite[Proposition~7.10]{BB-cohMod}; this may not be so easy to generalise, and the statement may need to change.

For these reasons, we leave positive characteristic analogues of~\cite[Theorem~1.11]{BB-cohMod} to future work.
\end{rema}


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